Question

Write the Nernst Equation and calculate Emf of the following cell at 298K: Mg(s)/Mg2+(0.001M) || Cu2+(0.0001M)/Cu(s). : 2+/ 0 = 0.34 V and 2+/ 0 = -2.37 V

Answer 1

Eo=0.34−(−2.37)=2.71 V

E=E0−(0.059​/n)log([Mg2+]/[Cu2+])​

E=2.71−(0.059/2)​log(0.0001/0.001​)

E=2.7395 V

Comments

1+1=2 hota hai

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number of electrons is 2

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electron ka hai

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thank you guys

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correct answer is 2.7395
E = 2.71- (0.059/2)(-1)